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Android使用httpPost向服务器发送请求的方法

作者:佚名      Android开发编辑:admin      更新时间:2022-07-23

本文实例讲述了Android使用httpPost向服务器发送请求的方法。分享给大家供大家参考,具体如下:

import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.conn.ConnectTimeoutException;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.CoreConnectionPNames;
import org.apache.http.protocol.HTTP;
import org.apache.http.util.EntityUtils;
import android.util.Log;
public class RequestByHttpPost {
  public static String TIME_OUT = "操作超时";
  public static String doPost(List<NameValuePair> params,String url) throws Exception{
    String result = null;
     // 新建HttpPost对象
     HttpPost httpPost = new HttpPost(url);
     // 设置字符集
     HttpEntity entity = new UrlEncodedFormEntity(params, HTTP.UTF_8);
     // 设置参数实体
     httpPost.setEntity(entity);
     // 获取HttpClient对象
     HttpClient httpClient = new DefaultHttpClient();
     //连接超时
     httpClient.getParams().setParameter(CoreConnectionPNames.CONNECTION_TIMEOUT, 30000);
     //请求超时
     httpClient.getParams().setParameter(CoreConnectionPNames.SO_TIMEOUT, 30000);
     try {
       // 获取HttpResponse实例
      HttpResponse httpResp = httpClient.execute(httpPost);
      // 判断是够请求成功
      if (httpResp.getStatusLine().getStatusCode() == 200) {
        // 获取返回的数据
        result = EntityUtils.toString(httpResp.getEntity(), "UTF-8");
        Log.i("HttpPost", "HttpPost方式请求成功,返回数据如下:");
        Log.i("result", result);
      } else {
        Log.i("HttpPost", "HttpPost方式请求失败");
      }
     } catch (ConnectTimeoutException e){
       result = TIME_OUT;
     }
     return result;
  }
}

可以直接用的完整类。

希望本文所述对大家Android程序设计有所帮助。