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Android模糊处理简单实现毛玻璃效果

作者:佚名      Android开发编辑:admin      更新时间:2022-07-23

自从iOS系统引入了Blur效果,也就是所谓的毛玻璃、模糊化效果、磨砂效果,各大系统就开始竞相模仿,这是怎样的一个效果呢,我们先来看一下,如下面的图片:

实现效果大家都知道了,如何在Android中实现呢,说白了就是对图片进行模糊化处理,小编先给大家讲一下Android高级模糊技术的原理,如下:

  • 首先我创建了一个空的bitmap,把背景的一部分复制进去,之后我会对这个bitmap进行模糊处理并设置为TextView的背景。
  • 通过这个bitmap保存Canvas的状态;
  • 在父布局文件中把Canvas移动到TextView的位置;
  • 把ImageView的内容绘到bitmap中;
  • 此时,我们就有了一个和TextView一样大小的bitmap,它包含了ImageView的一部分内容,也就是TextView背后一层布局的内容;
  • 创建一个Renderscript的实例;
  • 把bitmap复制一份到Renderscript需要的数据片中;
  • 创建Renderscript模糊处理的实例;
  • 设置输入,半径范围然后进行模糊处理;
  • 把处理后的结果复制回之前的bitmap中;
  • 好了,我们已经把bitmap惊醒模糊处理了,可以将它设置为TextView背景了;

我最近在做一款App,其中有一个功能需要对图片处理实现毛玻璃的特效,经过一番研究,找到了3中实现方案,其中各有优缺点,如果系统的api在16以上,可以使用系统提供的方法直接处理图片,但是小编认为下边的解决方案是实现效果最好的。
代码如下:

public Bitmap fastblur(Context context, Bitmap sentBitmap, int radius) { 
 
    Bitmap bitmap = sentBitmap.copy(sentBitmap.getConfig(), true); 
 
    if (radius < 1) { 
      return (null); 
    } 
 
    int w = bitmap.getWidth(); 
    int h = bitmap.getHeight(); 
 
    int[] pix = new int[w * h]; 
    bitmap.getPixels(pix, 0, w, 0, 0, w, h); 
 
    int wm = w - 1; 
    int hm = h - 1; 
    int wh = w * h; 
    int div = radius + radius + 1; 
 
    int r[] = new int[wh]; 
    int g[] = new int[wh]; 
    int b[] = new int[wh]; 
    int rsum, gsum, bsum, x, y, i, p, yp, yi, yw; 
    int vmin[] = new int[Math.max(w, h)]; 
 
    int divsum = (div + 1) >> 1; 
    divsum *= divsum; 
    int temp = 256 * divsum; 
    int dv[] = new int[temp]; 
    for (i = 0; i < temp; i++) { 
      dv[i] = (i / divsum); 
    } 
 
    yw = yi = 0; 
 
    int[][] stack = new int[div][3]; 
    int stackpointer; 
    int stackstart; 
    int[] sir; 
    int rbs; 
    int r1 = radius + 1; 
    int routsum, goutsum, boutsum; 
    int rinsum, ginsum, binsum; 
 
    for (y = 0; y < h; y++) { 
      rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; 
      for (i = -radius; i <= radius; i++) { 
        p = pix[yi + Math.min(wm, Math.max(i, 0))]; 
        sir = stack[i + radius]; 
        sir[0] = (p & 0xff0000) >> 16; 
        sir[1] = (p & 0x00ff00) >> 8; 
        sir[2] = (p & 0x0000ff); 
        rbs = r1 - Math.abs(i); 
        rsum += sir[0] * rbs; 
        gsum += sir[1] * rbs; 
        bsum += sir[2] * rbs; 
        if (i > 0) { 
          rinsum += sir[0]; 
          ginsum += sir[1]; 
          binsum += sir[2]; 
        } else { 
          routsum += sir[0]; 
          goutsum += sir[1]; 
          boutsum += sir[2]; 
        } 
      } 
      stackpointer = radius; 
 
      for (x = 0; x < w; x++) { 
 
        r[yi] = dv[rsum]; 
        g[yi] = dv[gsum]; 
        b[yi] = dv[bsum]; 
 
        rsum -= routsum; 
        gsum -= goutsum; 
        bsum -= boutsum; 
 
        stackstart = stackpointer - radius + div; 
        sir = stack[stackstart % div]; 
 
        routsum -= sir[0]; 
        goutsum -= sir[1]; 
        boutsum -= sir[2]; 
 
        if (y == 0) { 
          vmin[x] = Math.min(x + radius + 1, wm); 
        } 
        p = pix[yw + vmin[x]]; 
 
        sir[0] = (p & 0xff0000) >> 16; 
        sir[1] = (p & 0x00ff00) >> 8; 
        sir[2] = (p & 0x0000ff); 
 
        rinsum += sir[0]; 
        ginsum += sir[1]; 
        binsum += sir[2]; 
 
        rsum += rinsum; 
        gsum += ginsum; 
        bsum += binsum; 
 
        stackpointer = (stackpointer + 1) % div; 
        sir = stack[(stackpointer) % div]; 
 
        routsum += sir[0]; 
        goutsum += sir[1]; 
        boutsum += sir[2]; 
 
        rinsum -= sir[0]; 
        ginsum -= sir[1]; 
        binsum -= sir[2]; 
 
        yi++; 
      } 
      yw += w; 
    } 
    for (x = 0; x < w; x++) { 
      rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; 
      yp = -radius * w; 
      for (i = -radius; i <= radius; i++) { 
        yi = Math.max(0, yp) + x; 
 
        sir = stack[i + radius]; 
 
        sir[0] = r[yi]; 
        sir[1] = g[yi]; 
        sir[2] = b[yi]; 
 
        rbs = r1 - Math.abs(i); 
 
        rsum += r[yi] * rbs; 
        gsum += g[yi] * rbs; 
        bsum += b[yi] * rbs; 
 
        if (i > 0) { 
          rinsum += sir[0]; 
          ginsum += sir[1]; 
          binsum += sir[2]; 
        } else { 
          routsum += sir[0]; 
          goutsum += sir[1]; 
          boutsum += sir[2]; 
        } 
 
        if (i < hm) { 
          yp += w; 
        } 
      } 
      yi = x; 
      stackpointer = radius; 
      for (y = 0; y < h; y++) { 
        pix[yi] = (0xff000000 & pix[yi]) | (dv[rsum] << 16) 
            | (dv[gsum] << 8) | dv[bsum]; 
 
        rsum -= routsum; 
        gsum -= goutsum; 
        bsum -= boutsum; 
 
        stackstart = stackpointer - radius + div; 
        sir = stack[stackstart % div]; 
 
        routsum -= sir[0]; 
        goutsum -= sir[1]; 
        boutsum -= sir[2]; 
 
        if (x == 0) { 
          vmin[y] = Math.min(y + r1, hm) * w; 
        } 
        p = x + vmin[y]; 
 
        sir[0] = r[p]; 
        sir[1] = g[p]; 
        sir[2] = b[p]; 
 
        rinsum += sir[0]; 
        ginsum += sir[1]; 
        binsum += sir[2]; 
 
        rsum += rinsum; 
        gsum += ginsum; 
        bsum += binsum; 
 
        stackpointer = (stackpointer + 1) % div; 
        sir = stack[stackpointer]; 
 
        routsum += sir[0]; 
        goutsum += sir[1]; 
        boutsum += sir[2]; 
 
        rinsum -= sir[0]; 
        ginsum -= sir[1]; 
        binsum -= sir[2]; 
 
        yi += w; 
      } 
    } 
 
    bitmap.setPixels(pix, 0, w, 0, 0, w, h); 
    return (bitmap); 
  } 

以上就是本文的全部内容,帮助大家轻松实现毛玻璃效果,希望大家喜欢。